en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 2 of (3x^2+x)

Solution

\int_{1}^{2} (3 x^{2} + x) d x

Solution

\frac{17}{2}

+1

Decimal

8.5

Solution steps

\int_{1}^{2} 3 x^{2} + x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 3 x^{2} d x + \int_{1}^{2} x d x

\int_{1}^{2} 3 x^{2} d x = 7

\int_{1}^{2} x d x = \frac{3}{2}

= 7 + \frac{3}{2}

Simplify

7 + \frac{3}{2} : \frac{17}{2}

= \frac{17}{2}

Graph

Popular Examples

integral from-1 to 2 of (sin(x))/x

\int_{- 1}^{2} \frac{sin ( x )}{x} d x

integral from 0 to 1 of x/(2x^2+2)

\int_{0}^{1} \frac{x}{2 x ^{2} + 2} d x

integral from-2 to-1 of 2x(7-x^2)^3

\int_{- 2}^{- 1} 2 x (7 - x^{2})^{3} d x

integral from-2 to 2 of (4x^4-3x^2+5)

\int_{- 2}^{2} (4 x^{4} - 3 x^{2} + 5) d x

integral from 2 to 6 of 4x-12

\int_{2}^{6} 4 x - 12 d x

Frequently Asked Questions (FAQ)

What is the integral from 1 to 2 of (3x^2+x) ?
The integral from 1 to 2 of (3x^2+x) is 17/2