What is the integral from 1 to 4 of \sqrt[3]{x+3} ?

The integral from 1 to 4 of \sqrt[3]{x+3} is (21\sqrt[3]{7})/4-3\sqrt[3]{4}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 4 of \sqrt[3]{x+3}

\int_{1}^{4} 3 x + 3 d x

\frac{21 3 7}{4} - 334

Decimal

5.28068 \dots

Solution steps

\int_{1}^{4} 3 x + 3 d x

Apply u-substitution

: \int_{4}^{7} 3 u d u

= \int_{4}^{7} 3 u d u

Apply the Power Rule

: [\frac{3}{4} u^{\frac{4}{3}}]_{4}^{7}

= [\frac{3}{4} u^{\frac{4}{3}}]_{4}^{7}

Compute the boundaries:

\frac{21 3 7}{4} - 334

= \frac{21 3 7}{4} - 334

\int_{- 1}^{1} (2 x + ∣ x ∣ + 1)^{2} d x

\int_{3}^{9} \frac{1}{x ( ln ( x ) ) ^{6}} d x

\int_{0}^{1} 2 y^{2} (1 - y)^{x - 1} d y

\int_{- 2}^{1} (x - 2)^{2} d x

\int_{0}^{81} x d x

What is the integral from 1 to 4 of \sqrt[3]{x+3} ?
The integral from 1 to 4 of \sqrt[3]{x+3} is (21\sqrt[3]{7})/4-3\sqrt[3]{4}