What is the integral from 2 to infinity of e^{-x^2} ?

The integral from 2 to infinity of e^{-x^2} is 0.00414…

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 2 to infinity of e^{-x^2}

\int_{2}^{\infty} e^{- x^{2}} d x

0.00414 \dots

Solution steps

\int_{2}^{\infty} e^{- x^{2}} d x

Compute the indefinite integral:

\int e^{- x^{2}} d x = \frac{π}{2} erf (x) + C

Compute the boundaries:

\int_{2}^{\infty} e^{- x^{2}} d x = \frac{π}{2} - 0.88208 \dots

= \frac{π}{2} - 0.88208 \dots

Simplify

= 0.00414 \dots

\int_{\frac{π}{6}}^{\frac{5 π}{6}} (1 - 2 sin (x))^{2} d x

\int_{0}^{1} x^{5} (1 - x)^{3} d x

\int_{0}^{4 - z^{2}} z d z

\int_{0}^{0.75} 2 - 2 y d y

\int_{0}^{4} t e^{- 0.6 t} d t

What is the integral from 2 to infinity of e^{-x^2} ?
The integral from 2 to infinity of e^{-x^2} is 0.00414…