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Popular >

integral from-1 to 1 of (4-|x|)

Solution

\int_{- 1}^{1} (4 - ∣ x ∣) d x

Solution

7

Solution steps

\int_{- 1}^{1} 4 - ∣ x ∣ d x

Eliminate Absolutes

= \int_{- 1}^{0} 4 - (- x) d x + \int_{0}^{1} 4 - x d x

\int_{- 1}^{0} 4 - (- x) d x = \frac{7}{2}

\int_{0}^{1} 4 - x d x = \frac{7}{2}

= \frac{7}{2} + \frac{7}{2}

Simplify

\frac{7}{2} + \frac{7}{2} : 7

= 7

Graph

Popular Examples

integral from 1 to 2 of 2^{2x}

\int_{1}^{2} 2^{2 x} d x

integral from 0 to 1 of 9x^2-2x

\int_{0}^{1} 9 x^{2} - 2 x d x

integral from 2 to x^3 of 1/(x^2)

\int_{2}^{x^{3}} \frac{1}{x ^{2}} d x

integral from-pi to 0 of 3cos(nx)

\int_{- π}^{0} 3 cos (n x) d x

integral from 1 to 2 of x(x-1)(x-2)

\int_{1}^{2} x (x - 1) (x - 2) d x

Frequently Asked Questions (FAQ)

What is the integral from-1 to 1 of (4-|x|) ?
The integral from-1 to 1 of (4-|x|) is 7