What is the integral from 1 to 3 of (9/13 x^2-2) ?

The integral from 1 to 3 of (9/13 x^2-2) is 2

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integral from 1 to 3 of (9/13 x^2-2)

\int_{1}^{3} (\frac{9}{13} x^{2} - 2) d x

2

Solution steps

\int_{1}^{3} \frac{9}{13} x^{2} - 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} \frac{9}{13} x^{2} d x - \int_{1}^{3} 2 d x

\int_{1}^{3} \frac{9}{13} x^{2} d x = 6

\int_{1}^{3} 2 d x = 4

= 6 - 4

Simplify

= 2

\int_{1}^{3} \frac{x ^{3}}{3} + \frac{1}{4 x} d x

\int_{0}^{1} (3 x + 4) e^{2 x} d x

\int_{- 3}^{1} 2 x - 3 d x

\int_{- 4}^{2} 8 - 2 x - x^{2} d x

\int_{- 1}^{3} 2 x^{2} - 4 x - 6 d x

What is the integral from 1 to 3 of (9/13 x^2-2) ?
The integral from 1 to 3 of (9/13 x^2-2) is 2