What is the integral from 0 to 2 of 1/((x+3)^3) ?

The integral from 0 to 2 of 1/((x+3)^3) is 8/225

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 2 of 1/((x+3)^3)

\int_{0}^{2} \frac{1}{( x + 3 ) ^{3}} d x

\frac{8}{225}

Decimal

0.03555 \dots

Solution steps

\int_{0}^{2} \frac{1}{( x + 3 ) ^{3}} d x

Apply u-substitution

: \int_{3}^{5} \frac{1}{u ^{3}} d u

= \int_{3}^{5} \frac{1}{u ^{3}} d u

Apply the Power Rule

: [- \frac{1}{2 u ^{2}}]_{3}^{5}

= [- \frac{1}{2 u ^{2}}]_{3}^{5}

Compute the boundaries:

\frac{8}{225}

= \frac{8}{225}

\int_{- 2}^{x} (16 t^{2} - 15 t) d t

\int_{0}^{2} (2 x - 3) (8 x^{2} + 2) d x

\int_{\frac{π}{4}}^{\frac{5 π}{4}} cos (x) d x

\int_{- 2}^{5} \frac{2}{3} d x

\int_{0}^{2 π} \frac{128}{15} d θ

What is the integral from 0 to 2 of 1/((x+3)^3) ?
The integral from 0 to 2 of 1/((x+3)^3) is 8/225