What is the integral from-0.1 to 0.9 of-1600x ?

The integral from-0.1 to 0.9 of-1600x is -640

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integral from-0.1 to 0.9 of-1600x

\int_{- 0.1}^{0.9} - 1600 x d x

- 640

Solution steps

\int_{- 0.1}^{0.9} - 1600 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 1600 \cdot \int_{- 0.1}^{0.9} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{- 0.1}^{0.9}

= - 1600 [\frac{x ^{2}}{2}]_{- 0.1}^{0.9}

Simplify

= - 1600 [0.5 x^{2}]_{- 0.1}^{0.9}

Compute the boundaries:

0.4

= - 1600 \cdot 0.4

Simplify

= - 640

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What is the integral from-0.1 to 0.9 of-1600x ?
The integral from-0.1 to 0.9 of-1600x is -640