What is the solution for y^{''}+6y^'+34y=0 ?

The solution for y^{''}+6y^'+34y=0 is y=e^{-3t}(c_{1}cos(5t)+c_{2}sin(5t))

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y^{''}+6y^'+34y=0

y^{^{''}} + 6 y^{^{'}} + 34 y = 0

y = e^{- 3 t} (c_{1} cos (5 t) + c_{2} sin (5 t))

Solution steps

y^{''} (t) + 6 y^{'} (t) + 34 y = 0

Solve linear ODE:

y = e^{- 3 t} (c_{1} cos (5 t) + c_{2} sin (5 t))

y = e^{- 3 t} (c_{1} cos (5 t) + c_{2} sin (5 t))

x \to 0 lim (\frac{5 x ^{3}}{x})

\frac{1}{4} x^{2}, 2 x^{2}, x - 3

\frac{\partial}{\partial x} (6 x (x^{2} + y^{2} + z^{2})^{2})

\int \frac{( 2 x ^{2} + 2 )}{( x ^{2} - 2 x + 2 ) ^{2}} d x

f (x) = 3 x^{4} - x^{3} - 5 x^{2} + 7, at x = 2

What is the solution for y^{''}+6y^'+34y=0 ?
The solution for y^{''}+6y^'+34y=0 is y=e^{-3t}(c_{1}cos(5t)+c_{2}sin(5t))