What is the integral from-2 to 3 of (x-1)^3 ?

The integral from-2 to 3 of (x-1)^3 is -65/4

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integral from-2 to 3 of (x-1)^3

\int_{- 2}^{3} (x - 1)^{3} d x

- \frac{65}{4}

Decimal

- 16.25

Solution steps

\int_{- 2}^{3} (x - 1)^{3} d x

Apply u-substitution

: \int_{- 3}^{2} u^{3} d u

= \int_{- 3}^{2} u^{3} d u

Apply the Power Rule

: [\frac{u ^{4}}{4}]_{- 3}^{2}

= [\frac{u ^{4}}{4}]_{- 3}^{2}

Compute the boundaries:

- \frac{65}{4}

= - \frac{65}{4}

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What is the integral from-2 to 3 of (x-1)^3 ?
The integral from-2 to 3 of (x-1)^3 is -65/4