What is the integral from 0 to 3 of 6e^x ?

The integral from 0 to 3 of 6e^x is 6(e^3-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 3 of 6e^x

\int_{0}^{3} 6 e^{x} d x

6 (e^{3} - 1)

Decimal

114.51322 \dots

Solution steps

\int_{0}^{3} 6 e^{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int_{0}^{3} e^{x} d x

Use the common integral:

\int e^{x} d x = e^{x}

= 6 [e^{x}]_{0}^{3}

Compute the boundaries:

e^{3} - 1

= 6 (e^{3} - 1)

\int_{0}^{2} x^{2} + x - 2 d x

\int_{e}^{2 e} x ln (x) d x

\int_{- L}^{L} cos (\frac{nπ x}{L}) d x

\int_{0}^{3} ∣ x ∣ d x

\int_{0}^{2} (2 x^{2} y + 5 y^{4}) d x

What is the integral from 0 to 3 of 6e^x ?
The integral from 0 to 3 of 6e^x is 6(e^3-1)