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Popular >

integral from-0.5 to 0 of b+2bx

Solution

\int_{- 0.5}^{0} b + 2 b x d x

Solution

0.25 b

Solution steps

\int_{- 0.5}^{0} b + 2 b x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 0.5}^{0} b d x + \int_{- 0.5}^{0} 2 b x d x

\int_{- 0.5}^{0} b d x = 0.5 b

\int_{- 0.5}^{0} 2 b x d x = - 0.25 b

= 0.5 b - 0.25 b

Simplify

= 0.25 b

Popular Examples

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\int_{- 1}^{1} (x^{5} - 4 x^{2} + x - 1) d x

integral from 0 to 1 of t^2+t

\int_{0}^{1} t^{2} + t d t

integral from 1 to 2 of tsqrt(1/2 t^2+6)

\int_{1}^{2} t \frac{1}{2} t^{2} + 6 d t

integral from 0 to 7 of 2x

\int_{0}^{7} 2 x d x

integral from-pi to pi of cos^2(kx)

\int_{- π}^{π} cos^{2} (k x) d x

Frequently Asked Questions (FAQ)

What is the integral from-0.5 to 0 of b+2bx ?
The integral from-0.5 to 0 of b+2bx is 0.25b