What is the integral from 1 to 6 of (3(ln(x))^2)/x ?

The integral from 1 to 6 of (3(ln(x))^2)/x is ln^3(6)

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integral from 1 to 6 of (3(ln(x))^2)/x

\int_{1}^{6} \frac{3 ( ln ( x ) ) ^{2}}{x} d x

ln^{3} (6)

Decimal

5.75226 \dots

Solution steps

\int_{1}^{6} \frac{3 ( ln ( x ) ) ^{2}}{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{1}^{6} \frac{( ln ( x ) ) ^{2}}{x} d x

Apply u-substitution

: \int_{0}^{l n (6)} u^{2} d u

= 3 \cdot \int_{0}^{l n (6)} u^{2} d u

Apply the Power Rule

: [\frac{u ^{3}}{3}]_{0}^{l n (6)}

= 3 [\frac{u ^{3}}{3}]_{0}^{l n (6)}

Compute the boundaries:

\frac{ln ^{3} ( 6 )}{3}

= 3 \cdot \frac{ln ^{3} ( 6 )}{3}

Simplify

= ln^{3} (6)

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What is the integral from 1 to 6 of (3(ln(x))^2)/x ?
The integral from 1 to 6 of (3(ln(x))^2)/x is ln^3(6)