What is the integral from 1 to 3 of 95+432t^2-12t ?

The integral from 1 to 3 of 95+432t^2-12t is 3886

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integral from 1 to 3 of 95+432t^2-12t

\int_{1}^{3} 95 + 432 t^{2} - 12 t d t

3886

Solution steps

\int_{1}^{3} 95 + 432 t^{2} - 12 t d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} 95 d t + \int_{1}^{3} 432 t^{2} d t - \int_{1}^{3} 12 t d t

\int_{1}^{3} 95 d t = 190

\int_{1}^{3} 432 t^{2} d t = 3744

\int_{1}^{3} 12 t d t = 48

= 190 + 3744 - 48

Simplify

= 3886

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What is the integral from 1 to 3 of 95+432t^2-12t ?
The integral from 1 to 3 of 95+432t^2-12t is 3886