What is the integral from 0 to 1 of x(x^2) ?

The integral from 0 to 1 of x(x^2) is 1/4

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integral from 0 to 1 of x(x^2)

\int_{0}^{1} x (x^{2}) d x

\frac{1}{4}

Decimal

0.25

Solution steps

\int_{0}^{1} x x^{2} d x

Simplify

x x^{2} : x^{3}

= \int_{0}^{1} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{0}^{1}

= [\frac{x ^{4}}{4}]_{0}^{1}

Compute the boundaries:

\frac{1}{4}

= \frac{1}{4}

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\int_{0}^{1} e^{- i wt} d t

\int_{0}^{2} \frac{1}{( 2 - x ) ^{\frac{4}{5}}} d x

\int_{0}^{1} 1 + x^{2} x d x

What is the integral from 0 to 1 of x(x^2) ?
The integral from 0 to 1 of x(x^2) is 1/4