What is the integral from 0 to 3 of (2x-5)^5 ?

The integral from 0 to 3 of (2x-5)^5 is -1302

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 3 of (2x-5)^5

\int_{0}^{3} (2 x - 5)^{5} d x

- 1302

Solution steps

\int_{0}^{3} (2 x - 5)^{5} d x

Apply u-substitution

: \int_{- 5}^{1} \frac{u ^{5}}{2} d u

= \int_{- 5}^{1} \frac{u ^{5}}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{- 5}^{1} u^{5} d u

Apply the Power Rule

: [\frac{u ^{6}}{6}]_{- 5}^{1}

= \frac{1}{2} [\frac{u ^{6}}{6}]_{- 5}^{1}

Compute the boundaries:

- 2604

= \frac{1}{2} (- 2604)

Simplify

= - 1302

\int_{2}^{3} \frac{ln ( x )}{x} d x

\int_{1}^{4} (\frac{x}{8} - \frac{7}{x}) d x

\int_{0}^{\frac{π}{2}} \frac{1}{2} d x

\int_{1}^{4} 7 x + x d x

\int_{0}^{2} x^{4} d x

What is the integral from 0 to 3 of (2x-5)^5 ?
The integral from 0 to 3 of (2x-5)^5 is -1302