What is the integral from 0 to 2 of 1/((x+4)^3) ?

The integral from 0 to 2 of 1/((x+4)^3) is 5/288

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 2 of 1/((x+4)^3)

\int_{0}^{2} \frac{1}{( x + 4 ) ^{3}} d x

\frac{5}{288}

Decimal

0.01736 \dots

Solution steps

\int_{0}^{2} \frac{1}{( x + 4 ) ^{3}} d x

Apply u-substitution

: \int_{4}^{6} \frac{1}{u ^{3}} d u

= \int_{4}^{6} \frac{1}{u ^{3}} d u

Apply the Power Rule

: [- \frac{1}{2 u ^{2}}]_{4}^{6}

= [- \frac{1}{2 u ^{2}}]_{4}^{6}

Compute the boundaries:

\frac{5}{288}

= \frac{5}{288}

\int_{0}^{1} 1 - z^{2} d z

\int_{0}^{4} (3 - x) d x

\int_{- 2}^{4} x ∣ x - 3 ∣ d x

\int_{0}^{\frac{π}{2}} cos (x) + 1 d x

\int_{1}^{2} (z + \frac{2}{z}) \cdot (z - \frac{2}{z}) d z

What is the integral from 0 to 2 of 1/((x+4)^3) ?
The integral from 0 to 2 of 1/((x+4)^3) is 5/288