What is the integral from-pi/3 to 0 of (sin(x)) ?

The integral from-pi/3 to 0 of (sin(x)) is -1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-pi/3 to 0 of (sin(x))

\int_{- \frac{π}{3}}^{0} (sin (x)) d x

- \frac{1}{2}

Decimal

- 0.5

Solution steps

\int_{- \frac{π}{3}}^{0} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{- \frac{π}{3}}^{0}

Compute the boundaries:

- \frac{1}{2}

= - \frac{1}{2}

\int_{1}^{5} \frac{1}{( 10 - x ) ^{2}} d x

\int_{- 5}^{10} 5 - ∣ x ∣ d x

\int_{1}^{4} x - 1 d x

\int_{0}^{x^{2}} \frac{1}{3 + x ^{3}} d y

\int_{0}^{7} 8 d x

What is the integral from-pi/3 to 0 of (sin(x)) ?
The integral from-pi/3 to 0 of (sin(x)) is -1/2