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Popular >

integral from 1 to 5 of (x^2+x)

Solution

\int_{1}^{5} (x^{2} + x) d x

Solution

\frac{160}{3}

+1

Decimal

53.33333 \dots

Solution steps

\int_{1}^{5} x^{2} + x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{5} x^{2} d x + \int_{1}^{5} x d x

\int_{1}^{5} x^{2} d x = \frac{124}{3}

\int_{1}^{5} x d x = 12

= \frac{124}{3} + 12

Simplify

\frac{124}{3} + 12 : \frac{160}{3}

= \frac{160}{3}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 1 to 5 of (x^2+x) ?
The integral from 1 to 5 of (x^2+x) is 160/3