What is the integral from 6 to infinity of 2/(x^3) ?

The integral from 6 to infinity of 2/(x^3) is 1/36

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 6 to infinity of 2/(x^3)

\int_{6}^{\infty} \frac{2}{x ^{3}} d x

\frac{1}{36}

Decimal

0.02777 \dots

Solution steps

\int_{6}^{\infty} \frac{2}{x ^{3}} d x

Compute the indefinite integral:

\int \frac{2}{x ^{3}} d x = - \frac{1}{x ^{2}} + C

Compute the boundaries:

\int_{6}^{\infty} \frac{2}{x ^{3}} d x = 0 - (- \frac{1}{36})

= 0 - (- \frac{1}{36})

Simplify

= \frac{1}{36}

\int_{3}^{1} \frac{1}{x ^{2} + 1} d x

\int_{0}^{5} x^{2} - x d x

\int_{0}^{3} \frac{x e ^{x^{2}}}{3} d x

\int_{- 1}^{0} e^{- x} - e^{x} d x

\int_{- 9}^{0} (1 + 81 - x^{2}) d x

What is the integral from 6 to infinity of 2/(x^3) ?
The integral from 6 to infinity of 2/(x^3) is 1/36