What is the integral from-1 to 1 of x(e^x+e^{-x}) ?

The integral from-1 to 1 of x(e^x+e^{-x}) is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-1 to 1 of x(e^x+e^{-x})

\int_{- 1}^{1} x (e^{x} + e^{- x}) d x

0

Solution steps

\int_{- 1}^{1} x (e^{x} + e^{- x}) d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

x (e^{x} + e^{- x}) :

Odd

= 0

\int_{4}^{16} \frac{1}{z} d z

\int_{1}^{2} 1 + 9 x d x

\int_{- 3}^{3} 2 d x

\int_{- 3}^{0} (6 x^{3} - 3 x^{2} - 9 x - 6) d x

\int_{0}^{1} e^{- (2 x - 1)^{2}} d x

What is the integral from-1 to 1 of x(e^x+e^{-x}) ?
The integral from-1 to 1 of x(e^x+e^{-x}) is 0