What is the integral from-1.25 to 0 of (5x^3-3x+6) ?

The integral from-1.25 to 0 of (5x^3-3x+6) is 6.79199…

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-1.25 to 0 of (5x^3-3x+6)

\int_{- 1.25}^{0} (5 x^{3} - 3 x + 6) d x

6.79199 \dots

Solution steps

\int_{- 1.25}^{0} 5 x^{3} - 3 x + 6 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1.25}^{0} 5 x^{3} d x - \int_{- 1.25}^{0} 3 x d x + \int_{- 1.25}^{0} 6 d x

\int_{- 1.25}^{0} 5 x^{3} d x = - 3.05175 \dots

\int_{- 1.25}^{0} 3 x d x = - 2.34375

\int_{- 1.25}^{0} 6 d x = 7.5

= - 3.05175 \dots - (- 2.34375) + 7.5

Simplify

= 6.79199 \dots

\int_{0}^{1} x cos (\frac{nπ}{2} x) d x

\int_{2}^{x} - \frac{2}{t ^{3}} d t

\int_{0}^{x} e^{- t^{3}} d t

\int_{4}^{6} x^{2} + 2 x + 2 d x

\int_{0}^{2} π (16 - x^{4}) d x

What is the integral from-1.25 to 0 of (5x^3-3x+6) ?
The integral from-1.25 to 0 of (5x^3-3x+6) is 6.79199…