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Popular >

integral from-1 to 1 of 1+x

Solution

\int_{- 1}^{1} 1 + x d x

Solution

2

Solution steps

\int_{- 1}^{1} 1 + x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 1 d x + \int_{- 1}^{1} x d x

\int_{- 1}^{1} 1 d x = 2

\int_{- 1}^{1} x d x = 0

= 2 + 0

Simplify

= 2

Graph

Popular Examples

integral from 0 to 1 of (4t-1)^2

\int_{0}^{1} (4 t - 1)^{2} d t

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\int_{0}^{4} π (x + 3)^{2} d x

integral from 2 to 3 of x^2+2x+2-5

\int_{2}^{3} x^{2} + 2 x + 2 - 5 d x

integral from 0 to 2 of 1/(xln(x))

\int_{0}^{2} \frac{1}{x ln ( x )} d x

integral from 0 to 2 of sqrt(1+t^2)

\int_{0}^{2} 1 + t^{2} d t

Frequently Asked Questions (FAQ)

What is the integral from-1 to 1 of 1+x ?
The integral from-1 to 1 of 1+x is 2