What is the integral from 0 to pi of 2e^x-7cos(x) ?

The integral from 0 to pi of 2e^x-7cos(x) is 2(e^pi-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to pi of 2e^x-7cos(x)

\int_{0}^{π} 2 e^{x} - 7 cos (x) d x

2 (e^{π} - 1)

Decimal

44.28138 \dots

Solution steps

\int_{0}^{π} 2 e^{x} - 7 cos (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{π} 2 e^{x} d x - \int_{0}^{π} 7 cos (x) d x

\int_{0}^{π} 2 e^{x} d x = 2 (e^{π} - 1)

\int_{0}^{π} 7 cos (x) d x = 0

= 2 (e^{π} - 1) - 0

Simplify

= 2 (e^{π} - 1)

\int_{- 3}^{6} (- \frac{2}{3} x + 5) d x

\int_{- 1}^{2} (4 - x^{2}) - (x^{2} - 2 x) d x

\int_{- 5}^{0} cos (\frac{nπ x}{5}) d x

\int_{0}^{2} x e^{2 x^{2}} d x

\int_{- 1}^{1} (3 t - 8) d t

What is the integral from 0 to pi of 2e^x-7cos(x) ?
The integral from 0 to pi of 2e^x-7cos(x) is 2(e^pi-1)