What is the tangent of f(x)=x^2+9,(-4,25) ?

The tangent of f(x)=x^2+9,(-4,25) is y=-8x-7

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tangent of f(x)=x^2+9,(-4,25)

tangent of

f (x) = x^{2} + 9, (- 4, 25)

y = - 8 x - 7

Solution steps

Find the slope of

f (x) = x^{2} + 9 : \frac{df ( x )}{d x} = 2 x

Compute the slope of

f (x) = x^{2} + 9

(- 4, 25) : m = - 8

Find the line with slope m=

- 8

and passing through

(- 4, 25) : y = - 8 x - 7

y = - 8 x - 7

\int \frac{1}{( 1 - x ) ^{4}} d x

\frac{\partial}{\partial x} (8 e^{y x} - x^{2} y^{3})

\int 10 e^{- 10 x} d x

\int - \frac{8}{π} x d x

f (x) = \frac{2}{1 + e ^{- x}}, (0, 1)

What is the tangent of f(x)=x^2+9,(-4,25) ?
The tangent of f(x)=x^2+9,(-4,25) is y=-8x-7