What is the integral from 0 to pi of 3sin(t) ?

The integral from 0 to pi of 3sin(t) is 6

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integral from 0 to pi of 3sin(t)

\int_{0}^{π} 3 sin (t) d t

6

Solution steps

\int_{0}^{π} 3 sin (t) d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{0}^{π} sin (t) d t

Use the common integral:

\int sin (t) d t = - cos (t)

= 3 [- cos (t)]_{0}^{π}

Compute the boundaries:

2

= 3 \cdot 2

Simplify

= 6

\int_{- 2}^{2} 3 6^{\frac{x}{2}} d x

\int_{0}^{3} x \frac{2 x}{9} d x

\int_{1}^{2} 1 - x^{2} d x

\int_{0}^{b} \frac{1}{x ^{2} - 4} d x

\int_{0}^{2 π} 3 cos (x) sin (x) d x

What is the integral from 0 to pi of 3sin(t) ?
The integral from 0 to pi of 3sin(t) is 6