What is the integral from 0 to 2 of (x^4)/4 ?

The integral from 0 to 2 of (x^4)/4 is 8/5

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integral from 0 to 2 of (x^4)/4

\int_{0}^{2} \frac{x ^{4}}{4} d x

\frac{8}{5}

Decimal

1.6

Solution steps

\int_{0}^{2} \frac{x ^{4}}{4} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int_{0}^{2} x^{4} d x

Apply the Power Rule

: [\frac{x ^{5}}{5}]_{0}^{2}

= \frac{1}{4} [\frac{x ^{5}}{5}]_{0}^{2}

Compute the boundaries:

\frac{32}{5}

= \frac{1}{4} \cdot \frac{32}{5}

Simplify

= \frac{8}{5}

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What is the integral from 0 to 2 of (x^4)/4 ?
The integral from 0 to 2 of (x^4)/4 is 8/5