What is the integral from 0 to pi/4 of 9sec^2(t) ?

The integral from 0 to pi/4 of 9sec^2(t) is 9

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integral from 0 to pi/4 of 9sec^2(t)

\int_{0}^{\frac{π}{4}} 9 sec^{2} (t) d t

9

Solution steps

\int_{0}^{\frac{π}{4}} 9 sec^{2} (t) d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int_{0}^{\frac{π}{4}} sec^{2} (t) d t

Use the common integral:

\int sec^{2} (t) d t = tan (t)

= 9 [tan (t)]_{0}^{\frac{π}{4}}

Compute the boundaries:

1

= 9 \cdot 1

Simplify

= 9

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What is the integral from 0 to pi/4 of 9sec^2(t) ?
The integral from 0 to pi/4 of 9sec^2(t) is 9