What is the integral from-1 to 1 of x^3-3/5 x ?

The integral from-1 to 1 of x^3-3/5 x is 0

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integral from-1 to 1 of x^3-3/5 x

\int_{- 1}^{1} x^{3} - \frac{3}{5} x d x

0

Solution steps

\int_{- 1}^{1} x^{3} - \frac{3}{5} x d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

x^{3} - \frac{3}{5} x :

Odd

= 0

\int_{1}^{2} (x + 1)^{2} d x

\int_{- 2}^{0} x^{3} 16 - x^{4} d x

\int_{0}^{1} x^{2} 3 x^{3} + 1 d x

\int_{- 3}^{4} x^{2} + sin (x) + e^{x} d x

\int_{0}^{4} (2 x - 3 x) d x

What is the integral from-1 to 1 of x^3-3/5 x ?
The integral from-1 to 1 of x^3-3/5 x is 0