What is the integral from-1 to 0 of x^{1/3} ?

The integral from-1 to 0 of x^{1/3} is (3(-1)^{1/3})/4

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integral from-1 to 0 of x^{1/3}

\int_{- 1}^{0} x^{\frac{1}{3}} d x

\frac{3 ( - 1 ) ^{\frac{1}{3}}}{4}

Solution steps

\int_{- 1}^{0} x^{\frac{1}{3}} d x

Apply the Power Rule

: [\frac{3}{4} x^{\frac{4}{3}}]_{- 1}^{0}

= [\frac{3}{4} x^{\frac{4}{3}}]_{- 1}^{0}

Compute the boundaries:

(- 1)^{\frac{1}{3}} \frac{3}{4}

= (- 1)^{\frac{1}{3}} \frac{3}{4}

Simplify

= \frac{3 ( - 1 ) ^{\frac{1}{3}}}{4}

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What is the integral from-1 to 0 of x^{1/3} ?
The integral from-1 to 0 of x^{1/3} is (3(-1)^{1/3})/4