What is the integral from-3 to 3 of 1/x ?

The integral from-3 to 3 of 1/x is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-3 to 3 of 1/x

\int_{- 3}^{3} \frac{1}{x} d x

diverges

Solution steps

\int_{- 3}^{3} \frac{1}{x} d x

Find undefined (singularity) points:

x = 0

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{- 3}^{0} \frac{1}{x} d x + \int_{0}^{3} \frac{1}{x} d x

\int_{- 3}^{0} \frac{1}{x} d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

\int_{1}^{2} x (x^{2} + 1)^{4} d x

\int_{0}^{x} 13 + 14 t^{2} d t

\int_{- 1}^{0} x (3 x^{2} + 1) d x

\int_{0}^{4 - y^{2}} 2 x y d x

\int_{0}^{x} 4 e^{- 4 x} d x

What is the integral from-3 to 3 of 1/x ?
The integral from-3 to 3 of 1/x is diverges