What is the tangent of y= 2/x ,(-2,-1) ?

The tangent of y= 2/x ,(-2,-1) is y=-1/2 x-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y= 2/x ,(-2,-1)

tangent of

y = \frac{2}{x}, (- 2, - 1)

y = - \frac{1}{2} x - 2

Solution steps

Find the slope of

y = \frac{2}{x} : \frac{d y}{d x} = - \frac{2}{x ^{2}}

Compute the slope of

y = \frac{2}{x}

(- 2, - 1) : m = - \frac{1}{2}

Find the line with slope m=

- \frac{1}{2}

and passing through

(- 2, - 1) : y = - \frac{1}{2} x - 2

y = - \frac{1}{2} x - 2

\int \frac{x}{2 x ^{3}} d x

x \to 1 lim (5 x^{5} - 8 x^{3} + 8)

\int 3 sin (4 x) + 4 sin (3 x) d x

\frac{d y}{d x} = x^{3} e^{x^{4}}

x \to 2 lim ((2 - x)^{2})

What is the tangent of y= 2/x ,(-2,-1) ?
The tangent of y= 2/x ,(-2,-1) is y=-1/2 x-2