What is the integral from 1 to 5 of x^{2/3} ?

The integral from 1 to 5 of x^{2/3} is 3*5^{2/3}-3/5

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integral from 1 to 5 of x^{2/3}

\int_{1}^{5} x^{\frac{2}{3}} d x

3 \cdot 5^{\frac{2}{3}} - \frac{3}{5}

Decimal

8.17205 \dots

Solution steps

\int_{1}^{5} x^{\frac{2}{3}} d x

Apply the Power Rule

: [\frac{3}{5} x^{\frac{5}{3}}]_{1}^{5}

= [\frac{3}{5} x^{\frac{5}{3}}]_{1}^{5}

Compute the boundaries:

3 \cdot 5^{\frac{2}{3}} - \frac{3}{5}

= 3 \cdot 5^{\frac{2}{3}} - \frac{3}{5}

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\int_{0}^{2} 5 x^{3} d x

What is the integral from 1 to 5 of x^{2/3} ?
The integral from 1 to 5 of x^{2/3} is 3*5^{2/3}-3/5