What is the integral from 0 to 9 of (2sqrt(x))^2 ?

The integral from 0 to 9 of (2sqrt(x))^2 is 162

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integral from 0 to 9 of (2sqrt(x))^2

\int_{0}^{9} (2 x)^{2} d x

162

Solution steps

\int_{0}^{9} (2 x)^{2} d x

Apply Integration By Parts

: [4 x^{2} - \int 4 x d x]_{0}^{9}

= [4 x^{2} - \int 4 x d x]_{0}^{9}

\int 4 x d x = 2 x^{2}

= [4 x^{2} - 2 x^{2}]_{0}^{9}

Simplify

= [2 x^{2}]_{0}^{9}

Compute the boundaries:

162

= 162

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What is the integral from 0 to 9 of (2sqrt(x))^2 ?
The integral from 0 to 9 of (2sqrt(x))^2 is 162