What is the derivative of-4cos(2x) ?

The derivative of-4cos(2x) is 8sin(2x)

What is the first derivative of-4cos(2x) ?

The first derivative of-4cos(2x) is 8sin(2x)

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derivative of

- 4 cos (2 x)

8 sin (2 x)

Solution steps

\frac{d}{d x} (- 4 cos (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 4 \frac{d}{d x} (cos (2 x))

Apply the chain rule:

- sin (2 x) \frac{d}{d x} (2 x)

= - sin (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= - 4 (- sin (2 x) \cdot 2)

Simplify

= 8 sin (2 x)

\frac{d}{d x} (x^{5} e^{x} cos (x))

\int x^{2} - 2 x + 5 d x

\int \frac{1}{x ^{2} + 3} d x

\frac{1}{x - 8}

r = cos (2 θ)

What is the derivative of-4cos(2x) ?
The derivative of-4cos(2x) is 8sin(2x)
What is the first derivative of-4cos(2x) ?
The first derivative of-4cos(2x) is 8sin(2x)