What is the integral from 1 to 2 of-6/(x^2) ?

The integral from 1 to 2 of-6/(x^2) is -3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 2 of-6/(x^2)

\int_{1}^{2} - \frac{6}{x ^{2}} d x

- 3

Solution steps

\int_{1}^{2} - \frac{6}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 6 \cdot \int_{1}^{2} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{1}^{2}

= - 6 [- \frac{1}{x}]_{1}^{2}

Compute the boundaries:

\frac{1}{2}

= - 6 \cdot \frac{1}{2}

Simplify

= - 3

\int_{1}^{e} \frac{ln ( x ^{4} )}{x} d x

\int_{2}^{3} \frac{1}{3} d x

\int_{0}^{2} 4 x - \frac{x ^{3}}{3} d x

\int_{2}^{x^{2}} \frac{sin ( t )}{t} d t

\int_{0}^{2} \frac{1}{( x + 1 )} d x

What is the integral from 1 to 2 of-6/(x^2) ?
The integral from 1 to 2 of-6/(x^2) is -3