What is the integral from 0 to 1 of 8t^2 ?

The integral from 0 to 1 of 8t^2 is 8/3

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integral from 0 to 1 of 8t^2

\int_{0}^{1} 8 t^{2} d t

\frac{8}{3}

Decimal

2.66666 \dots

Solution steps

\int_{0}^{1} 8 t^{2} d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 8 \cdot \int_{0}^{1} t^{2} d t

Apply the Power Rule

: [\frac{t ^{3}}{3}]_{0}^{1}

= 8 [\frac{t ^{3}}{3}]_{0}^{1}

Compute the boundaries:

\frac{1}{3}

= 8 \cdot \frac{1}{3}

Simplify

= \frac{8}{3}

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What is the integral from 0 to 1 of 8t^2 ?
The integral from 0 to 1 of 8t^2 is 8/3