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Popular >

integral from-1 to 0 of (8x-1)

Solution

\int_{- 1}^{0} (8 x - 1) d x

Solution

- 5

Solution steps

\int_{- 1}^{0} 8 x - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{0} 8 x d x - \int_{- 1}^{0} 1 d x

\int_{- 1}^{0} 8 x d x = - 4

\int_{- 1}^{0} 1 d x = 1

= - 4 - 1

Simplify

= - 5

Graph

Popular Examples

integral from 1 to 3 of (-x^2+4x)

\int_{1}^{3} (- x^{2} + 4 x) d x

integral from-1 to 5 of x^2

\int_{- 1}^{5} x^{2} d x

integral from 0 to 2 of (x-2)^4

\int_{0}^{2} (x - 2)^{4} d x

integral from 0 to b of x^3

\int_{0}^{b} x^{3} d x

integral from 2 to 4 of (2/x+3x)

\int_{2}^{4} (\frac{2}{x} + 3 x) d x

Frequently Asked Questions (FAQ)

What is the integral from-1 to 0 of (8x-1) ?
The integral from-1 to 0 of (8x-1) is -5