What is the integral from-2 to 4 of (2x-4-2x^{1/2}) ?

The integral from-2 to 4 of (2x-4-2x^{1/2}) is -32/3-Does not exist

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-2 to 4 of (2x-4-2x^{1/2})

\int_{- 2}^{4} (2 x - 4 - 2 x^{\frac{1}{2}}) d x

- \frac{32}{3} - Does not exist

Solution steps

\int_{- 2}^{4} 2 x - 4 - 2 x^{\frac{1}{2}} d x

Compute the indefinite integral:

\int 2 x - 4 - 2 x^{\frac{1}{2}} d x = x^{2} - 4 x - \frac{4}{3} x^{\frac{3}{2}} + C

Compute the boundaries:

\int_{- 2}^{4} (2 x - 4 - 2 x^{\frac{1}{2}}) d x = - \frac{32}{3} -

Does not exist

= - \frac{32}{3} - Does not exist

\int_{0}^{1} x sin (n) π x d x

\int_{5}^{10} x^{2} + 5 d x

\int_{0}^{8} 9 x^{2} + 3 d x

\int_{0}^{2} (2^{x} + x^{2}) d x

\int_{0}^{1} x (1 - x^{2})^{\frac{1}{2}} d x

What is the integral from-2 to 4 of (2x-4-2x^{1/2}) ?
The integral from-2 to 4 of (2x-4-2x^{1/2}) is -32/3-Does not exist