What is the integral from 1.7 to 4.7 of 2t^{1/2} ?

The integral from 1.7 to 4.7 of 2t^{1/2} is 10.63043…

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integral from 1.7 to 4.7 of 2t^{1/2}

\int_{1.7}^{4.7} 2 t^{\frac{1}{2}} d t

10.63043 \dots

Solution steps

\int_{1.7}^{4.7} 2 t^{\frac{1}{2}} d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{1.7}^{4.7} t^{\frac{1}{2}} d t

Apply the Power Rule

: [\frac{2}{3} t^{\frac{3}{2}}]_{1.7}^{4.7}

= 2 [\frac{2}{3} t^{\frac{3}{2}}]_{1.7}^{4.7}

Simplify

= 2 [0.66666 \dots t^{\frac{3}{2}}]_{1.7}^{4.7}

Compute the boundaries:

5.31521 \dots

= 2 \cdot 5.31521 \dots

Simplify

= 10.63043 \dots

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What is the integral from 1.7 to 4.7 of 2t^{1/2} ?
The integral from 1.7 to 4.7 of 2t^{1/2} is 10.63043…