What is the integral from 0 to 100pi of sin(x) ?

The integral from 0 to 100pi of sin(x) is 0

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integral from 0 to 100pi of sin(x)

\int_{0}^{100 π} sin (x) d x

0

Solution steps

\int_{0}^{100 π} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{0}^{100 π}

Compute the boundaries:

0

= 0

\int_{1}^{3} 6 d x

\int_{- 1}^{0} 2 x + x^{2} - x^{3} d x

\int_{0}^{5} u^{2} + u + 1 d u

\int_{0}^{\infty} e^{- (x)} d x

\int_{0}^{5} t e^{- 0.3 t} d t

What is the integral from 0 to 100pi of sin(x) ?
The integral from 0 to 100pi of sin(x) is 0