What is the integral from 2 to 6 of 5/x-(10)/(x^2) ?

The integral from 2 to 6 of 5/x-(10)/(x^2) is 5ln(3)-10/3

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integral from 2 to 6 of 5/x-(10)/(x^2)

\int_{2}^{6} \frac{5}{x} - \frac{10}{x ^{2}} d x

5 ln (3) - \frac{10}{3}

Decimal

2.15972 \dots

Solution steps

\int_{2}^{6} \frac{5}{x} - \frac{10}{x ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{6} \frac{5}{x} d x - \int_{2}^{6} \frac{10}{x ^{2}} d x

\int_{2}^{6} \frac{5}{x} d x = 5 ln (3)

\int_{2}^{6} \frac{10}{x ^{2}} d x = \frac{10}{3}

= 5 ln (3) - \frac{10}{3}

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What is the integral from 2 to 6 of 5/x-(10)/(x^2) ?
The integral from 2 to 6 of 5/x-(10)/(x^2) is 5ln(3)-10/3