What is the integral from-2 to 5 of h(x) ?

The integral from-2 to 5 of h(x) is (21h)/2

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integral from-2 to 5 of h(x)

\int_{- 2}^{5} h (x) d x

\frac{21 h}{2}

Solution steps

\int_{- 2}^{5} h x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= h \cdot \int_{- 2}^{5} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{- 2}^{5}

= h [\frac{x ^{2}}{2}]_{- 2}^{5}

Compute the boundaries:

\frac{21}{2}

= h \frac{21}{2}

Simplify

= \frac{21 h}{2}

\int_{0}^{1} - x^{3} + 4 x^{2} - 3 x d x

\int_{- 5}^{0} (5 + 25 - x^{2}) d x

\int_{5}^{7} 2 x d x

\int_{1}^{8} (x^{2} - 4 x - 12) d x

\int_{0}^{1} 2 x^{2} + 1 d x

What is the integral from-2 to 5 of h(x) ?
The integral from-2 to 5 of h(x) is (21h)/2