What is the integral from 1 to e of 1/x ln(x) ?

The integral from 1 to e of 1/x ln(x) is 1/2

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integral from 1 to e of 1/x ln(x)

\int_{1}^{e} \frac{1}{x} ln (x) d x

\frac{1}{2}

Decimal Notation

0.5

Solution steps

\int_{1}^{e} \frac{1}{x} ln (x) d x

Apply u-substitution

: \int_{0}^{1} u d u

= \int_{0}^{1} u d u

Apply the Power Rule

: [\frac{u ^{2}}{2}]_{0}^{1}

= [\frac{u ^{2}}{2}]_{0}^{1}

Compute the boundaries:

\frac{1}{2}

= \frac{1}{2}

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What is the integral from 1 to e of 1/x ln(x) ?
The integral from 1 to e of 1/x ln(x) is 1/2