What is the integral from 0 to pi/6 of (cos(x)) ?

The integral from 0 to pi/6 of (cos(x)) is 1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to pi/6 of (cos(x))

\int_{0}^{\frac{π}{6}} (cos (x)) d x

\frac{1}{2}

Decimal Notation

0.5

Solution steps

\int_{0}^{\frac{π}{6}} cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= [sin (x)]_{0}^{\frac{π}{6}}

Compute the boundaries:

\frac{1}{2}

= \frac{1}{2}

\int_{- 2}^{0} (3 x - 2 e^{x}) d x

\int_{0}^{2} - x^{3} + x^{2} + 2 x d x

\int_{0}^{8} ∣ x - 3 ∣ d x

\int_{0}^{1} 4 x - 6 (x^{2})^{\frac{1}{3}} d x

\int_{- 1}^{3} (3 x - 5) (x + 2) d x

What is the integral from 0 to pi/6 of (cos(x)) ?
The integral from 0 to pi/6 of (cos(x)) is 1/2