What is the integral from-1 to 1 of (e^x-e^{-x})/2 ?

The integral from-1 to 1 of (e^x-e^{-x})/2 is 0

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integral from-1 to 1 of (e^x-e^{-x})/2

\int_{- 1}^{1} \frac{e ^{x} - e ^{- x}}{2} d x

0

Solution steps

\int_{- 1}^{1} \frac{e ^{x} - e ^{- x}}{2} d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

\frac{e ^{x} - e ^{- x}}{2} :

Odd

= 0

\int_{0}^{3} 1 - x^{2} d x

\int_{4}^{\infty} \frac{1}{x ^{2}} d x

\int_{0}^{4} (4 - x^{2}) - (4 - 4 x) d x

\int_{5}^{x^{2}} 2 1 + x^{2} d x

\int_{0}^{1} ln ∣ x + 1 ∣ d x

What is the integral from-1 to 1 of (e^x-e^{-x})/2 ?
The integral from-1 to 1 of (e^x-e^{-x})/2 is 0