What is laplacetransform te^{,\at} ?

The answer to laplacetransform te^{,\at} is e^{,\at} 1/(s^2)

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laplacetransform te^{,\at}

laplace transform

t e^{, at}

e^{, at} \frac{1}{s ^{2}}

Solution steps

L {e^{, at} t}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= e^{, at} L {t}

L {t} : \frac{1}{s ^{2}}

= e^{, at} \frac{1}{s ^{2}}

\frac{d}{d x} (20 x^{2})

\frac{d ^{2}}{d x ^{2}} (\frac{sin ( x )}{x})

y^{^{''}} + 8 y^{^{'}} + 16 y = 0, y (0) = - 4, y^{^{'}} (0) = 21

\frac{d ^{2}}{d x ^{2}} (x (3 x + 2)^{5})

What is laplacetransform te^{,\at} ?
The answer to laplacetransform te^{,\at} is e^{,\at} 1/(s^2)