What is the integral from 2 to 5 of 1/(xln(x)) ?

The integral from 2 to 5 of 1/(xln(x)) is ln(ln(5))-ln(ln(2))

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integral from 2 to 5 of 1/(xln(x))

\int_{2}^{5} \frac{1}{x ln ( x )} d x

ln (ln (5)) - ln (ln (2))

Decimal Notation

0.84239 \dots

Solution steps

\int_{2}^{5} \frac{1}{x ln ( x )} d x

Apply u-substitution

: \int_{l n (2)}^{l n (5)} \frac{1}{u} d u

= \int_{l n (2)}^{l n (5)} \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= [ln ∣ u ∣]_{l n (2)}^{l n (5)}

Compute the boundaries:

ln (ln (5)) - ln (ln (2))

= ln (ln (5)) - ln (ln (2))

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What is the integral from 2 to 5 of 1/(xln(x)) ?
The integral from 2 to 5 of 1/(xln(x)) is ln(ln(5))-ln(ln(2))