What is the integral from 0 to 4 of xsqrt(25-x^2) ?

The integral from 0 to 4 of xsqrt(25-x^2) is 98/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 4 of xsqrt(25-x^2)

\int_{0}^{4} x 25 - x^{2} d x

\frac{98}{3}

Decimal Notation

32.66666 \dots

Solution steps

\int_{0}^{4} x 25 - x^{2} d x

Apply u-substitution

: \int_{25}^{9} - \frac{u}{2} d u

= \int_{25}^{9} - \frac{u}{2} d u

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{9}^{25} - \frac{u}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - (- \frac{1}{2} \cdot \int_{9}^{25} u d u)

Apply the Power Rule

: [\frac{2}{3} u^{\frac{3}{2}}]_{9}^{25}

= - (- \frac{1}{2} [\frac{2}{3} u^{\frac{3}{2}}]_{9}^{25})

Simplify

= \frac{1}{2} [\frac{2}{3} u^{\frac{3}{2}}]_{9}^{25}

Compute the boundaries:

\frac{196}{3}

= \frac{1}{2} \cdot \frac{196}{3}

Simplify

= \frac{98}{3}

\int_{x}^{1} (x + y) d y

\int_{3}^{5} 25 - x^{2} d x

\int_{0.5}^{1} 3 e^{- 3 x} d x

\int_{1}^{2} (3 x - 5 x + 1) d x

\int_{1}^{3} k x^{2} d x

What is the integral from 0 to 4 of xsqrt(25-x^2) ?
The integral from 0 to 4 of xsqrt(25-x^2) is 98/3