What is the integral from 2 to 4 of-6/(x^2) ?

The integral from 2 to 4 of-6/(x^2) is -3/2

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integral from 2 to 4 of-6/(x^2)

\int_{2}^{4} - \frac{6}{x ^{2}} d x

- \frac{3}{2}

Decimal Notation

- 1.5

Solution steps

\int_{2}^{4} - \frac{6}{x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 6 \cdot \int_{2}^{4} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{2}^{4}

= - 6 [- \frac{1}{x}]_{2}^{4}

Compute the boundaries:

\frac{1}{4}

= - 6 \cdot \frac{1}{4}

Simplify

= - \frac{3}{2}

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What is the integral from 2 to 4 of-6/(x^2) ?
The integral from 2 to 4 of-6/(x^2) is -3/2