What is the integral from 1 to 2 of sqrt(x^2) ?

The integral from 1 to 2 of sqrt(x^2) is 3/2

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integral from 1 to 2 of sqrt(x^2)

\int_{1}^{2} x^{2} d x

\frac{3}{2}

Decimal Notation

1.5

Solution steps

\int_{1}^{2} x^{2} d x

Apply exponent rule:

a^{2} = ∣ a ∣

= \int_{1}^{2} ∣ x ∣ d x

Eliminate Absolutes

= \int_{1}^{2} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{1}^{2}

= [\frac{x ^{2}}{2}]_{1}^{2}

Compute the boundaries:

\frac{3}{2}

= \frac{3}{2}

\int_{- 1}^{2} 2 x - x^{2} d x

\int_{1}^{3} - 2 x d x

\int_{1}^{4} 5^{2 x} d x

\int_{0}^{\frac{1}{2}} (2 x) d x

\int_{- 1}^{2} 9 - x^{2} d x

What is the integral from 1 to 2 of sqrt(x^2) ?
The integral from 1 to 2 of sqrt(x^2) is 3/2